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X^2-2X=3024
We move all terms to the left:
X^2-2X-(3024)=0
a = 1; b = -2; c = -3024;
Δ = b2-4ac
Δ = -22-4·1·(-3024)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-110}{2*1}=\frac{-108}{2} =-54 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+110}{2*1}=\frac{112}{2} =56 $
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